Optimal. Leaf size=129 \[ -\frac {b c d x^{2+m} \sqrt {1-c^2 x^2}}{(3+m)^2}+\frac {d x^{1+m} (a+b \text {ArcSin}(c x))}{1+m}-\frac {c^2 d x^{3+m} (a+b \text {ArcSin}(c x))}{3+m}-\frac {b c d (7+3 m) x^{2+m} \text {Hypergeometric2F1}\left (\frac {1}{2},\frac {2+m}{2},\frac {4+m}{2},c^2 x^2\right )}{(1+m) (2+m) (3+m)^2} \]
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Rubi [A]
time = 0.11, antiderivative size = 129, normalized size of antiderivative = 1.00, number of steps
used = 4, number of rules used = 5, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.217, Rules used = {14, 4777, 12,
470, 371} \begin {gather*} -\frac {c^2 d x^{m+3} (a+b \text {ArcSin}(c x))}{m+3}+\frac {d x^{m+1} (a+b \text {ArcSin}(c x))}{m+1}-\frac {b c d (3 m+7) x^{m+2} \, _2F_1\left (\frac {1}{2},\frac {m+2}{2};\frac {m+4}{2};c^2 x^2\right )}{(m+1) (m+2) (m+3)^2}-\frac {b c d \sqrt {1-c^2 x^2} x^{m+2}}{(m+3)^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 14
Rule 371
Rule 470
Rule 4777
Rubi steps
\begin {align*} \int x^m \left (d-c^2 d x^2\right ) \left (a+b \sin ^{-1}(c x)\right ) \, dx &=\frac {d x^{1+m} \left (a+b \sin ^{-1}(c x)\right )}{1+m}-\frac {c^2 d x^{3+m} \left (a+b \sin ^{-1}(c x)\right )}{3+m}-(b c) \int \frac {d x^{1+m} \left (\frac {1}{1+m}-\frac {c^2 x^2}{3+m}\right )}{\sqrt {1-c^2 x^2}} \, dx\\ &=\frac {d x^{1+m} \left (a+b \sin ^{-1}(c x)\right )}{1+m}-\frac {c^2 d x^{3+m} \left (a+b \sin ^{-1}(c x)\right )}{3+m}-(b c d) \int \frac {x^{1+m} \left (\frac {1}{1+m}-\frac {c^2 x^2}{3+m}\right )}{\sqrt {1-c^2 x^2}} \, dx\\ &=-\frac {b c d x^{2+m} \sqrt {1-c^2 x^2}}{(3+m)^2}+\frac {d x^{1+m} \left (a+b \sin ^{-1}(c x)\right )}{1+m}-\frac {c^2 d x^{3+m} \left (a+b \sin ^{-1}(c x)\right )}{3+m}-\frac {(b c d (7+3 m)) \int \frac {x^{1+m}}{\sqrt {1-c^2 x^2}} \, dx}{(1+m) (3+m)^2}\\ &=-\frac {b c d x^{2+m} \sqrt {1-c^2 x^2}}{(3+m)^2}+\frac {d x^{1+m} \left (a+b \sin ^{-1}(c x)\right )}{1+m}-\frac {c^2 d x^{3+m} \left (a+b \sin ^{-1}(c x)\right )}{3+m}-\frac {b c d (7+3 m) x^{2+m} \, _2F_1\left (\frac {1}{2},\frac {2+m}{2};\frac {4+m}{2};c^2 x^2\right )}{(1+m) (2+m) (3+m)^2}\\ \end {align*}
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Mathematica [A]
time = 0.04, size = 118, normalized size = 0.91 \begin {gather*} -\frac {d x^{1+m} \left ((2+m) \left (-3+c^2 x^2+m \left (-1+c^2 x^2\right )\right ) (a+b \text {ArcSin}(c x))+b c (1+m) x \text {Hypergeometric2F1}\left (-\frac {1}{2},1+\frac {m}{2},2+\frac {m}{2},c^2 x^2\right )+2 b c x \text {Hypergeometric2F1}\left (\frac {1}{2},1+\frac {m}{2},2+\frac {m}{2},c^2 x^2\right )\right )}{(1+m) (2+m) (3+m)} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 2.48, size = 0, normalized size = 0.00 \[\int x^{m} \left (-c^{2} d \,x^{2}+d \right ) \left (a +b \arcsin \left (c x \right )\right )\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} - d \left (\int \left (- a x^{m}\right )\, dx + \int \left (- b x^{m} \operatorname {asin}{\left (c x \right )}\right )\, dx + \int a c^{2} x^{2} x^{m}\, dx + \int b c^{2} x^{2} x^{m} \operatorname {asin}{\left (c x \right )}\, dx\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int x^m\,\left (a+b\,\mathrm {asin}\left (c\,x\right )\right )\,\left (d-c^2\,d\,x^2\right ) \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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